9^2x^+1=1/27

Solution for 9^2x^+1=1/27 equation:

9^2x^+1=1/27

We move all terms to the left:

9^2x^+1-(1/27)=0

We add all the numbers together, and all the variables

9^2x^+1-(+1/27)=0

We get rid of parentheses

9^2x^+1-1/27=0

We multiply all the terms by the denominator


9^2x^*27-1+1*27=0

We add all the numbers together, and all the variables

9^2x^*27+26=0

Wy multiply elements

243x^2+26=0

a = 243; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·243·26
Δ = -25272
Delta is less than zero, so there is no solution for the equation